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9th June strip
Posted: Thu Jun 09, 2005 1:37 am
by BlasTech
Heh, those brownies definately dont like squidge
panel 3 just cracked me up
Must compliment quent on his new outfit, and the headgear
Preliminary translation of the brownie language
Squidge: Hello gnomes, i am ally?
Gnomes: Ha! Bug Eye!! Kill the Scum!
Squidge: YAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA!
Dont know if there's anything in the next line, looks just like random warcries
And when he holds up the spear
"Eh, North Tribe?"
Posted: Thu Jun 09, 2005 2:11 am
by Astral
Aww poor squidge
Posted: Thu Jun 09, 2005 2:52 am
by Fusion
POOR SQUIDGE?!?
Posted: Thu Jun 09, 2005 7:16 am
by CasVeg
If the white stag keeps licking Quentyn, he just might end up with a big white mohawk.
Okay, maybe not; but, I still can't get the image out of my head.
Posted: Thu Jun 09, 2005 7:31 am
by SolidusRaccoon
CasVeg wrote:If the white stag keeps licking Quentyn, he just might end up with a big white mohawk.
Okay, maybe not; but, I still can't get the image out of my head.
I Pity the Foo' who messes with the Questor.
Posted: Thu Jun 09, 2005 8:07 am
by The JAM
[...unWARP!!!]
Good evening.
What does the LRR mean? It can't be a street name...a sector name, perhaps?
Posted: Thu Jun 09, 2005 1:19 pm
by DracoDei
Branches to take on the streets from the center of town (hexagonal streetmaps remember? Although that might only be Sanctuary...)
Left
Right
Right
Posted: Thu Jun 09, 2005 6:57 pm
by UncleMonty
I'm 'way too lazy to work out what the brownies are saying, but at least Quentyn's got this tribe's attention. Hmmm... I hope the tribes aren't warring with each other!
It's getting harder to find a thread for this forum that isn't dedicated to fanfic, too. I'm glad THIS thread exists even if I don't have a clue as to what's going on in the comic!
Posted: Thu Jun 09, 2005 7:33 pm
by The JAM
[...unWARP!!!]
Good evening.
Squidge: "Hello, Gnomes! I am ally?"
Brownie: "HAI!! Bogey! Kill the scum!"
Squidge: "EEEEYAAAAGH!!!!"
Brownies: "Ungawa! Tuk tuk tuk arrgh!"
[after Quentyn calms everyone down]
Brownie: "Eh? North Tribe?"
Posted: Thu Jun 09, 2005 9:02 pm
by RedSquirrel456
Branches to take on the streets from the center of town (hexagonal streetmaps remember? Although that might only be Sanctuary...)
Left
Right
Right
Two wrongs don't make a right, but two rights make a one hundred eighty degree turn...
Posted: Thu Jun 09, 2005 10:23 pm
by StrangeWulf13
Only if those rights equal 90 degrees. Which, in a circular city, they don't.
Divide 360 by 3 to get the angle...
120 degrees, going by the outside. So, to find the inside angle, we subtract 120 from 180.
The left and right turns are 60 degrees each, if you face the middle of the fork and turn until you're facing down one of the streets.
=P Little bit of math never hurt anyone. Calculus on the other hand...
...well, the United Nations is currently sending inspectors to look into suspected war crimes commited by this hideous beast in classrooms worldwide. Math teachers are advised to comply with their requests under threat of invasion by the United States without UN approval.
Ya might wanna duck and cover when you see the marines knocking on your classroom door...
Posted: Fri Jun 10, 2005 1:51 am
by BlasTech
ahhh calculus ... a true weapon of maths instruction
Posted: Fri Jun 10, 2005 1:56 am
by Astral
StrangeWulf13 wrote:Only if those rights equal 90 degrees. Which, in a circular city, they don't.
Divide 360 by 3 to get the angle...
120 degrees, going by the outside. So, to find the inside angle, we subtract 120 from 180.
The left and right turns are 60 degrees each, if you face the middle of the fork and turn until you're facing down one of the streets.
AAHHHHH!! PLEASE make him staawwwppp!
I'll be good I'll bee Good I promise! I'll even go to bed on time without a fus, just please no more maths!
Posted: Fri Jun 10, 2005 3:26 am
by SolidusRaccoon
BlasTech wrote:ahhh calculus ... a true weapon of maths instruction
Grrr, you are really pushing your luck today.
Posted: Fri Jun 10, 2005 4:51 am
by Shyal_malkes
((9x+2)/(3x^2-2x-8))+((7)/3x^2+x-4)
now simplify and solve as best you can!
you have never lived until you take a class that you fear will be challenging and on the fourth day you have progressed beyond any skill you have otherwise developed yet and you STILL understand every word the teacher says!
Posted: Fri Jun 10, 2005 8:32 am
by Trump
shyal_malkes wrote:((9x+2)/(3x^2-2x-8))+((7)/3x^2+x-4)
now simplify and solve as best you can!
you have never lived until you take a class that you fear will be challenging and on the fourth day you have progressed beyond any skill you have otherwise developed yet and you STILL understand every word the teacher says!
Did you mean to put an extra set of parenthesis around the 3x^2+x-4 part? Also should I assume the smiley to be 8 with an extra parenthesis?
Posted: Fri Jun 10, 2005 8:37 am
by Aurrin
I'm fairly sure he meant it like this:
Code: Select all
9x + 2 7
--------------- + --------------
3x^2 - 2x - 8 3x^2 + x - 4
Posted: Fri Jun 10, 2005 10:38 am
by Shyal_malkes
somehow i must have hit a code thingy and my 8 parentheses was interperated as a smiley
great my first smiley and it was a total accident!
8) lets see if it does it again...
Posted: Fri Jun 10, 2005 10:41 am
by Shyal_malkes
yes it did and yes aurrin you are correct that is how it looks like in my notes (this was prob 64 that our teacher was reviewing with us, i forget what page number or really what book it was, not that it matters.)
Posted: Wed Jun 15, 2005 6:57 am
by CasVeg
Code: Select all
9x + 2 7
[1.1] ------------- + ------------
3x^2 - 2x - 8 3x^2 + x - 4
The quadratic expressions can be factored.
Code: Select all
9x + 2 7
[1.2] --------------- + ---------------
(3x + 4)(x - 2) (3x + 4)(x - 1)
Partial fraction decomposition may now be used on each of the rational expressions.
The first expression:
Code: Select all
A B 9x + 2
[1.3] ------ + ----- = ---------------
3x + 4 x - 2 (3x + 4)(x - 2)
Multiplying by the least common denominator,
This yields the following system of equations:
Code: Select all
[1.5] A + 3B = 9
[1.6] -2A + 4B = 2
or
[1.7] -A + 2B = 1
[1.5] and [1.7] may be added to eliminate A.
By substitution,
So,
Code: Select all
9x + 2 3 2
[1.10] --------------- = ------ + -----
(3x + 4)(x - 1) 3x + 4 x - 2
The second expression:
Code: Select all
A B 7
[1.11] ------ + ----- = ---------------
3x + 4 x - 2 (3x + 4)(x - 1)
Multiplying by the least common denominator,
This yields the following system of equations:
Code: Select all
[1.13] A + 3B = 0
[1.14] -A + 4B = 7
[1.13] and [1.14] may be added to eliminate A.
By substitution,
So,
Code: Select all
7 -3 1
[1.17] --------------- = ------ + -----
(3x + 4)(x - 1) 3x + 4 x - 1
Substituting back into [1.2],
Code: Select all
3 2 3 1
------ + ----- - ------ + -----
3x + 4 x - 2 3x + 4 x - 1
2 1
[1.18] ----- + -----
x - 2 x - 1
What? I like taking the scenic route. Besides, I couldn't pass up a chance to use partial fractions!
Okay, okay. . . Math
is the art of doing as little work as possible. . . .
Code: Select all
9x + 2 7
[2.1] ------------- + ------------
3x^2 - 2x - 8 3x^2 + x - 4
The quadratic expressions can be factored.
Code: Select all
9x + 2 7
[2.2] --------------- + ---------------
(3x + 4)(x - 2) (3x + 4)(x - 1)
The rational expressions may be added together.
Code: Select all
(9x + 2)(x - 1) + 7(x - 2)
--------------------------
(3x + 4)(x - 2)(x - 1)
9x^2 - 16
[2.3] ----------------------
(3x + 4)(x - 2)(x - 1)
The numerator in [2.3] is a difference of squares.
Code: Select all
(3x + 4)(3x - 4)
[2.4] ----------------------
(3x + 4)(x - 2)(x - 1)
[2.4] is simplified by cancelling 3x + 4 in the numerator and denominator.
Code: Select all
3x - 4
[2.5] --------------
(x - 2)(x - 1)
As this is an expression, it can't actually be "solved". However, it is worth noting that the expression is equal to zero when x = 4/3 and undefined when x = 1, x = 2, or x = -4/3. The latter is true because 3x + 4 was in the denominators in the original expression.
P.S.: When you make a post, there is an option to disable smilies. I have mine disabled by default. 8)