o/~ Screaming in the shower... o/~

o/~ Screaming in the shower... o/~

Postby Woapalanne on Mon Mar 15, 2004 11:24 pm

Image

I am a bad, bad man. Mmmm...
Yes, I'm the wierdo that does <A HREF="http://ucrats.keenspace.com" TARGET=_blank>Image</A>.
And I'm Woap, not Woa, and very not Anne :)
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Postby Elizabeth Sherry on Tue Mar 16, 2004 9:03 am

bad... like a naked girl running out of a shower!

I gotta say, this has got to be one of the nicest things anyone has ever done to a sketch of mine! All that digital inking probably took you longer to do than the original took me to draw.
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Postby Elizabeth Sherry on Tue Mar 16, 2004 11:44 am

Wow, this seems to be a popular image. I should draw naked women more often.

Anyway, this is from a friend of mine who doesn't read the strip, by the name of Alan Cook. Like so many artists, he has a Piro complex.

So without further ado, and minus digital inking (but plus pretty shading), Occultech's latest ad:

Image
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Postby Woapalanne on Tue Mar 16, 2004 1:32 pm

Elizabeth Sherry wrote: All that digital inking probably took you longer to do than the original took me to draw.


I've watched you draw, so that's possibly true. ;)
Yes, I'm the wierdo that does <A HREF="http://ucrats.keenspace.com" TARGET=_blank>Image</A>.
And I'm Woap, not Woa, and very not Anne :)
Woapalanne
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Location: Tucson, AZ

Postby Vlion on Thu Apr 29, 2004 11:20 pm

*puzzled*
Piro complex?
/b
| f(x) dx = F(b) - F(a)
/a
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Postby Elizabeth Sherry on Fri Apr 30, 2004 2:51 pm

Whoops, my fangirl-nerdishness is showing again. A Piro complex refers to an artist who constantly puts himself down ("I suck, I'm a hack, I can't draw" etc.). It's a joking term that originally referred to Fred Gallagher (AKA Piro), creator of Megatokyo (at least to the best of my knowledge). So what I mean to say is that my friend is a very good artist but refuses to admit it.
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Postby Doruk on Thu May 06, 2004 8:10 am

Alternately known as the Doruk Complex :P
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Postby Vlion on Sun May 09, 2004 6:49 pm

ahhhhh....I see.
sefl-deprecation. :)
/b
| f(x) dx = F(b) - F(a)
/a
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Postby Elizabeth Sherry on Tue May 11, 2004 1:18 pm

Exactly.
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